3) If sin Q = 4/5 than find cos Q.
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Answered by
3
sin Q=4/5
sin theta =perpendicular upon hypotenuse
then perpendicularis 4and the hypotenuse is 5
using Pythagoras theorem (H) ^2=(P) ^2+(B) ^2
5^2 = 4^2+B^2
Base =√25-16
base is 3
cos theta is base upon hypotenuse
then cos Q is 3/5
hope this helps you......
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Aarchel:
why
Answered by
4
sin Q = perpendicular ÷ hypotenuse
cos Q = base ÷ hypotenuse
Now, base =√hypotenuse² - √perpendicular²
base = √25-16
:- base = 3
So, cos Q =3/5
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