Question

3.
If SinA = cos (A-6°), find the value of A​

Answer 1

Answer:

your ans

Step-by-step explanation:

sin A = sin { 90°-(A-6°)}

=>A=90°-A+6

=>A+A=96°

=>2A=96°

=>A=48°

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Answer 2

Answer:

Hello mate✌✌✌

Given :

sin A = cos (A - 6°)

=> cos (90 - A°) = cos (A - 6°)

Eliminating 'cos' from both sides :

90 - A = A - 6

=> A + A = 90 + 6

=> 2A = 96

=> A = 96/2

=> A = 48°

Hope it helps✌✌✌