Question

3) If tan 0 = 2, then find sec 0. ​

Answer 1

Answer:

$1 \: + { \tan(0) }^{2} = { \sec(0) }^{2} \\ = > 1 + {2 }^{2} = { \sec(0) }^{2} \\ = > \sec \: (0) = \sqrt{1 + {2}^{2} } \\ = > \: \sec(0) = \sqrt{5}$