Question

3. If tan 2A = cot (A-18°), where 2A is an acute angle, find the value of A.
4. If tan A=cot B, prove that A+B= 90.​

Answer 1

Answer:

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Step-by-step explanation:

Given tan2A=cot(A−18 0 )

⇒cot(90−2A)=cot(A−18 0) [∵tanθ=cot(90−θ)]

Comparing angles we get

90−2A=A−18

⇒90+18=A+2A

⇒3A=108

⇒A= 3

108

⇒A=36°