Question

3. If the angles of a triangle are (x+20), (x-40)
and 1 /2 (x+40), find the value of x and all
three angles.​

Answer 1

in∆

angles are (x+20), (x-40) and 1/2(x+40)

then (x+20)+(x-40)+1/2(x+40)= 180°

=5X=180×2

5x=360°

x=360/5

x=72

then

x+20= 72+20

=92°

x-40= 72-40

=32°

1/2(x+40)

=1/2(72+40)

=56°

angle of ∆

92° , 32° and 56° and

value of x= 72

I hope it's helpful

Answer 2

this is the solution of your question

thanks

hope it will help you