(3) If the area of a trapezium with parallel sides of lengths 30 cm and 23 cm respectively is 265 sq cm, what is its
height?
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Step-by-step explanation:
Ar(ABCD) = h(a + b)/2
=> 265 = h(30 + 23)/2
=> 265 = h × 53/2
=> 265 × 2/53 = h
.°. h = 265 × 2/53 = 10 cm
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