Physics, asked by saniya190, 7 months ago

(3) If the dimensions of e/(4πε0hc), where ‘e’ is electronic charge, ε0 is absolute electrical permittivity of free space, h is Planck’s constant and c is the speed of light in vacum can be expressed of the form MaLbTc. Find the value of a*b*c.

Answers

Answered by jothika132002
0

Explanation:

Planck's constant (h) has joule-seconds unit, dimensions are =[ML

2

T

−1

]

Electron charge (e) will have [TI]

Dimension for ε

0

is [M

−1

L

−3

T

4

I

2

]

Dimensions for

4πε

0

hc

e

2

will be [M

0

L

0

T

0

].

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