Question

3. If the function f:[1,00)→: [1,00) is defined by f(x) = 2*(x-1), then f-1(x) is
a)(1/2)*(x-1)
c) 1/2(1+/1 - 4 logz x]
b)1/2(1+/1 + 4 log2 x]
d)not defined​

Answer 1

Answer:

ANSWER

f(x)=2  

x(x+1)

, i.e.,  y=2  

x(x+1)

,

⇒log  

2

​  

y=x(x−1)=x  

2

−x

⇒x  

2

−x−log  

2

​  

y=0

⇒x=  

2

1±  

1+4log  

2

​  

y

​  

 

​  

 

Since x∈[1,∞)   ∴ -ve sign is ruled out.

∴⇒x=  

2

1

​  

(1+  

1+4log  

2

​  

y

​  

)

⇒f  

−1

(x)=  

2

1

​  

(1+  

1+4log  

2

​  

y

​  

)

⇒f  

−1

(x)=  

2

1

​  

(1+  

1+4log  

2

​  

x

Step-by-step explanation: