Math, asked by gauravgupta111102, 8 months ago


3. If the H.C.E of 56 and 72 is expressible in the form of 56x + 72 x 53, then find the value of x.
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Answers

Answered by aavika279
1

Answer:

According to Euclid division Lemma,

72=56*1+1656

=16*3+816

=8*2+0…….

So, 8 is the HCF.

Now 8=56-(16*3)…..

8 is expressed in terms of 56 and 16, but it should be in the form of 56 and 72.

Hence by splliting 16 we get,

8=56-(72-56*1)(3)

8 =56-72*3+56*3…….

Since we have one more 56 is grouped as

8 =56*4+72(-3).

So,X and Y are 4,3 respectively ..

Therefore X and Y are not equal.

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