Question

3. If the peak alternating current in a circuit is 21.2 A,
find out the reading of an ammeter connected in the
circuit.
Ans. 15 A.

Answer 1

Answer:

the answer is correct which you have given

Answer 2

Given: The peak alternating current is 21.2 A in a circuit.

To find: Reading of ammeter in the circuit

Explanation: In alternating current, the current regularly changes value and direction after a fixed period of time. Its value fluctuates between RMS( root mean square) value and its peak value.

The ammeter connected in a circuit measures its RMS value. The peak value of current and RMS value is related by the equation:

$peak \: current = \sqrt{2} rms \: current$

Here, 21.2 A is the peak current

For rms current,

=$\frac{peak \: current}{ \sqrt{2} }$

=$\frac{21.2}{ \sqrt{2} }$

= 15 A

Therefore, the reading of ammeter in the circuit is 15 A.