Question

3) if the ratio of the sum of the first n terms of two APs(7n–1) : (4n+27) then find the ratio of the their 9th term

sn= 7n+1/ sn1= 4n+27​

Answer 1

Answer:

ratio of n terms =(7n-1):(4n+27)

1st AP=7n-1

2nd AP =4n+27

1st AP 9th term

7(9)+1=64

2nd AP 9th term

4(9)+27=63

solution,

ratio of two AP's 9 the term=64:63

64:63