Question

3. If the ratio of volumes of two spheres is 1:8, then the ratio of their surface
areas is
a) 1:2
b) 1:4
c) 1:8
d) 1:16​

Answer 1

Answer:

◦•●◉✿plz mark me as brainleist✌✌✌✌✌✿◉●•◦

◦•●◉✿ans is b 1:4✿◉●•◦

Step-by-step explanation:

◦•●◉✿Volume of a sphere of radius 'r' =

3

4

πr

3

Let r

1

be the radius of the first sphere and r

2

and be the radius of the second sphere.

Given, ratio of their volumes is: V

1

:V

2

=1:8

3

4

πr

1

3

:

3

4

πr

3

2

h=1:8

r

1

3

:r

2

3

=1:8

=>r

1

:r

2

=1:2

Surface area of a sphere of radius 'r' =4πr

2

Now, ratio of their surface areas is:

S

1

:S

2

=4πr

1

2

:4πr

2

2

h

=r

1

2

:r

2

2

=1

2

:2

2

=1:4

◦•●◉✿A

✿◉●•◦✿◉●•◦

Answer 2

Answer:

it means ,

2×1:8

=2:16

cut it by table of 2

=1:8.....