Math, asked by Adityaabanve, 3 months ago

(3)
If the roots of the equation mx - 3mx + 9 = 0 are real and equal, find the
value of m.​

Answers

Answered by arpitasinghchauhan8
2

Answer:

We know that while finding the root of a quadratic equation ax

2

+bx+c=0 by quadratic formula x=

2a

−b±

b

2

−4ac

,

if b

2

−4ac>0, then the roots are real and distinct

if b

2

−4ac=0, then the roots are real and equal and

if b

2

−4ac<0, then the roots are imaginary.

Here, the given quadratic equation x

2

−mx+9=0 is in the form ax

2

+bx+c=0 where a=1,b=−m and c=9.

(i) If the roots are equal then b

2

−4ac=0, therefore,

b

2

−4ac=0

⇒(−m)

2

−(4×1×9)=0

⇒m

2

−36=0

⇒m

2

=36

⇒m=±

36

⇒m=±6

(ii) If the roots are distinct then b

2

−4ac>0, therefore,

b

2

−4ac>0

⇒(−m)

2

−(4×1×9)>0

⇒m

2

−36>0

⇒m

2

>36

⇒m>±

36

⇒m>±6

(iii) If the roots are imaginary then b

2

−4ac<0, therefore,

b

2

−4ac<0

⇒(−m)

2

−(4×1×9)<0

⇒m

2

−36<0

⇒m

2

<36

⇒m<±

36

⇒m<±6

Hence m=±6 if the roots are equal, m>±6 if the roots are distinct and m<±6 if the roots are imaginary.

Step-by-step explanation:

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