3. If the side of a rhombus is 10 cm and one diagonal is 16 cm, then find the area of the
rhombus.
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the diagonals of rhombous are perpendicular bisectors
the rhombous is comprised of four right angle triangles with each side as hypotenuse and half the diagonals as sides, hence
half the other diagonal =√ side^2 - half the one diagonal^2
= √10^2 - 8^2
= √100-64
=√36
= 6 cm
hence length of other diagonal is 2*6 = 12 cm
area of rhombous = (1/2)* product of diagonals
= (1/2)*18*12
= 108 sqcm
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