Question

3. If the squared difference of the zeros of the quadratic polynomial f(x) = x++px + 45 is
equal to 144, find the value of p.​

Answer 1

Answer:

Let α,β be the zeroes of the given quadratic polynomial f(x)=x

2

+px+45

∴α+β=−p,αβ=45

It is given that, (α−β)

2

=144

⇒(α+β)

2

–4αβ=144

⇒(–p)

2

–4×45=144

⇒p

2

–180=144

⇒p

2

=144+180

⇒p

2

=324

⇒p=±

324

∴p=±18