3. If the sum of three numbers in an AP is 9 and their product is 24, then the numbers are
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6
Answer:
a+r+a+a-r=9
3a=9
a=3
(3+r)(3)(3-r)=24
3^2-r2=8
9-r2=8
r2=1
r=1
Therefore
a+r. a. a-r
4. 3. 2
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Answered by
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Answer:
hey mate
pls find ur answer attached above
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