* 3. If the usual uniform speed of a train is
increased by 5 km/h, it takes 48 minutes
less than the usual time to cover a distance
of 360 km. Find the usual uniform speed of
the train.
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Given :
- uniform speed of a train is increased by 5 km/h
- it takes 48 minutes less than the usual time
- cover a distance of 360 km.
To find :
- usual uniform speed of the train.
Solution:
Let initial speed of the train be x km/hr,
New speed is (x + 5) km/hr.
time to distance cover 350 km = distance/speed= 360/x hours
New time after increasing speed 360/x + 5 hours .... from given condition
360/x + 5 = 360/x - 48/60 (48 min = 48/60 hrs)
360/x - 360/x + 5 = 48/60
1/x - 1/x + 5 = 48/60 x 360 (Dividing both sides by 360)
x + 5 x/x (x + 5) 4/5 x 360
5/x² + 5x 1/5 x 90
5/x² + 5x 1/450
x² + 5x = 2250
x² + 5x - 2250 =0
x² + 50x - 45x - 2250 = 0
x(x + 50) - 45 (x + 50) = 0
(x + 50) (x - 45) =0
x + 50 = 0 or x - 45 = 0
x = -50 or = 45
But speed is never negative x ≠ -50
x = 45
=> Initial speed of the train is 45 km/hr.
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