Question

3. If the value of energy in Bohr orbit is -78 KCal/mole then the angular momentum of an electron in that orbit is * (4 Points)
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Answer 1

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En = 78.4 kcal/mole =>

78.4×4.2= 329.28 kJ/mole

= 96.5−329.28

eV = 3.4 eV, which is the energy of 2nd orbit of Hydrogen atom.

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