3. If x=6t3+4t2-2t+8 represent displacement of a body then find its velocity
and acceleration at t=2sec.
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Answered by
2
Answer:
the tropical preparation display of a body vehicles
Answered by
2
Answer:
v = 86 m/s
a = 80 m/s2
Explanation:
x=6t3+4t2-2t+8
v = d/dt ( x=6t3+4t2-2t+8)
= 18t2 + 8t -2
at t= 2 sec
v = 18(4) + 8(2) -2
= 72 +16 -2
= 88-2
= 86 m/s
a = d/dt ( 18t2 + 8t -2)
= 18*2 t +8
= 36t +8
at t= 2 sec
a = 36*2 +8
= 80 m/s2
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