Math, asked by aahanasodha, 6 months ago

3) If x : y =4:7, find [4x + 5y] [5x +3y]




plz answer this question in detail ​

Answers

Answered by abhi569
41

Answer:

51/41

Step-by-step explanation:

=> x/y = 4/7 → x = (4y/7)

Thus, 4x = 4(4y/7) = 16y/7

5x = 5(4y/7) = 20y/7

Hence,

4x + 5y = 16y/7 + 5y

= 51y/7

5x + 3y = 20y/7 + 3y

= 41y/7

Therefore,

(4x + 5y)/(5x + 3y) = (51y/7)/(41y/7)

= 51/41

Answered by Qᴜɪɴɴ
62

Given :

  • x: y= 4:7

━━━━━━━━━━━━━━━━━━━━

Need to Find:

  •  \dfrac{4x + 5y}{5x + 3y}  =

━━━━━━━━━━━━━━━━━━━━

Solution:

 \dfrac{x}{y}  =  \dfrac{4}{7}

 \implies \: 7x = 4y

\purple{\bold{ \implies \: y=  \dfrac{7x}{4} }}

Now substituting it in given equation we get,

 \dfrac{4x + 5y}{5x + 3y}

 =  \dfrac{4x +3 \times   \dfrac{7x}{4} }{5x + 3 \times \dfrac{7x}{4}  }

 =  \dfrac{4x +  \dfrac{35x}{4} }{5x +  \dfrac{21x}{4} }

 =  \dfrac{16x + 35x}{4}  \times  \dfrac{4}{20x + 21x}

\red{\bold{\large{\boxed{ =  \dfrac{51}{41} (Ans)}}}}

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