Math, asked by darshanmali289, 2 months ago

3.If ∆XYZ ~ ∆PQR and A(∆XYZ ) = 25 2

, A(∆PQR) = 4 2

then XY: PQ =?

(A) 4:25 (B)2:5 (C) 5:2 (D)25:4​

Answers

Answered by riteshaleti161
6

answer

A(∆XYZ)/A{∆PQR)=xy^2/pq^2

25/4=xy^2/pq^2

xy=5,pq=2

xy:pq::5:2

Answered by desaichandrakala16
8

Step-by-step explanation:

A(∆ABC)/A(∆PQR) = XY²/PQ²

25/4 = XY²/PQ²

Taking square root on both the sides

✓25/✓4 = ✓Xy²/✓PQ²

XY/PQ = 5/2

XY:PQ = 5:2

Similar questions