3. In a AABC, if DE is drawn parallel to BC, cutting AB and AC at D and E respectively such
that AB = 7.2 cm, AC = 6.4 cm and AD = 4.5 cm. Then AE = ?
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Given :-in a triangle ABC, DE is drawn parallel to BC (DE II BC)
DE cuts AB & AC at D & E respectively. AB=7.2 cm,AC=6.4 cm & AD=4.5 cm. Proof:-As, DE II BC(Given),So, According to Basic Proportionality Theorem /Thales Theorem AD/DB=AE/EC i.e AD/AB=AE/AC 4.5cm/7.2cm=AE/6.4 cm AE=4.5cm*6.4 cm/7.2 cm AE=4 cm(This is the required answer) [If you liked my answer then please mark me as brainliest and I will definitely follow you back.]
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