Question

3. In a bag there are 5 red balls, 4 yellow balls and 3 white balls. Find the probability of

a. getting a red ball

b. Not getting a white ball

with solution​

Answer 1

Answer:

a.5/12

b.9/12

thank you its my answer is it correct

Answer 2

Answer:

Question :-

In a bag there are 5 red balls, 4 yellow balls and 3 white balls. Find the probability of

a. getting a red ball

b. Not getting a white ball

Answer :-

a) The probability of getting a red ball is $\frac{5}{12}$

b) The probability of not getting a white ball is $\frac{3}{4}$

Given :-

• Red balls = 5
• Yellow balls = 4
• white balls = 3

To find :-

Find the probability of

a. getting a red ball

b. Not getting a white ball

Solution :-

Total number of balls = 5+4+3 = 12.

$\boxed{ \large{probability = \frac{number \: of \: favourable \: outcomes}{number \: of \: possible \: outcomes} }}$

a) Getting a red ball

Number of favourable outcomes = 5

$\implies \: probability \: (getting \: a \: red \: ball) = \frac{5}{12}$

Hence,

The probability of getting a red ball is $\frac{5}{12}$

b) not getting a white ball

Number of favourable outcomes = 5 + 4 = 9

$\implies \: probability \: (not \: getting \: a \: white \: ball) = \frac{9}{12} \\ \\ \implies \: probability \: (not \: getting \: a \: white \: ball) = \frac{3}{4}$

Hence,

The probability of not getting a white ball is $\frac{3}{4}$

.