3 In a circle chord AB = 8cm and radius of a circle 5cm find oc
Answers
Answered by
1
OC is perpendicular on chord AB
∴OC bisects the chord AB
⇒AC=CB
Now,
AC+CB=AB
⇒AC+CB=8
⇒AC=28
⇒4cm
△OCA is a right angled triangle
∴AO2=AC2+OC2
⇒52=42+OC2
⇒52−42=OC2
⇒OC2=9
⇒OC=3
Since, OD is the radius of the circle
∴OA=OD=5cm
CD=OD−OC
⇒5−3=2cm
Similar questions
Math,
16 hours ago
Computer Science,
16 hours ago
English,
1 day ago
Business Studies,
8 months ago
English,
8 months ago