Question

3 In a circle chord AB = 8cm and radius of a circle 5cm find oc​

Answer 1

OC is perpendicular on chord AB

∴OC bisects the chord AB

⇒AC=CB

Now,

AC+CB=AB

⇒AC+CB=8

⇒AC=28

       ⇒4cm

△OCA is a right angled triangle

∴AO2=AC2+OC2

⇒52=42+OC2

⇒52−42=OC2

⇒OC2=9

⇒OC=3

Since, OD is the radius of the circle

∴OA=OD=5cm

CD=OD−OC

⇒5−3=2cm