Question

3. In a public examination 90% students passed and 8,800 students failed. How many students appeared and how many passed?​

Answer 1

Answer:

Let the total students be x.

Passed students=90%×100=0.9x

Failed students=(100%−90%)x=0.1x

Given,

0.1x=80

⟹x=800

Hence total candidates=800

Answer 2

Answer:

88,000; 79,200

Step-by-step explanation:

let's consider students appeared for exam be 100

and 90% are passed i.e., 10% are failed.

So number of students failed = 10

but it is given 8,800 students are failed.

let's compare the problem with our assumption

8,800 = 10 x 880

Therefore Students appeared for exam

100 x 880 = 88,000

Students passed = 88,000 - 8,800

= 79,200