Question

3. In a quadrilateral ABCD, ZA = 150° and ZB = ZC = ZD, find ZB, ZC
and ZD.​

Answer 1

Step-by-step explanation:

i think its 150 bt send the pic of that question..

Answer 2

Answer:

Step-by-step explanation:

Let zb=zc=zd=x

Zb+zc+zd+za=360

X+x+x+150=360

3x=360-150

3x=210

X=210÷3

X=70

Zb+zc+zd=70