Question

3. In a right ABC; the lengths of sides are given below. Find the length of the hypotenuse:
0 0=3.5 m, b=5 m (m) a=7.5 m; b=18 m
4 SABC is right-angled at C.JF AC =5 cm and BC = 13 cm, find the length AB.​

Answer 1

Step-by-step explanation:

Let AB=10cm

Hypotenuse (AC)=26cm

BC=?

Then, by Pythagoras theorem

AC

2

=AB

2

+BC

2

c

2

=a

2

+b

2

c

2

=6

2

+(4.5)

2

c

2

=36+20.25

c

2

=56.25

Sending powers 2 from LHS to RHS it becomes square root

c=

56.25

c=7.5cm

The length of hypotenuse of a triangle is 7.5cm