Question

3. In a right angle triangle with side A and B and hypotenuse C, the altitude drawn on the hypotenuse is x . prove that AB=CX

Answer 1

CD perpendicular to AB

and CD = x

Area of ∆ABC = ( AB × CD )/2

= ( cx )/2 ----( 1 )

also

Area of ∆ABC = ( BC × AC )/2

= ( ab )/2 ------( 2 )

( 1 ) = ( 2 )

( cx )/2 = ( ab )/2

cx = ab

Hence proved

I hope this helps you.

: )