Question

3. In a Trapezium if the sum of the parallel sides is 16cm and the area is 48 cm², then its height
is
​

Answer 1

Answer:

Let height of trapezium be h cm

Sum of parallel sides = 16 cm

Area of trapezium = 48 cm²

Area of trapezium = 1/2 x sum of parallel sides x height

• 48 = 1/2 x 16 x h
• 48 = 8 x h
• 48/8 = h
• 6 = h

Height of trapezium = 6 cm

Answer 2

Answer:

height of the trapezium is  6cm.

Step-by-step explanation:

Given,Sum of parallel sides of trapezium is 16.

Let a and b be 2 parallel sides of trapezium. Then ,

a+b=16

Area of the trapezium is 48cm²

using area formula of trapezium,

A= $\frac{1}{2}$h(a+b)

were, a is the area of trapezium

          h is the height of te trapezium

          a,b are the two parallel sides of trapezium

a=48  h= not given a+b=16

then, 48=$\frac{1}{2}$×h×16

48=h×$\frac{16}{2}$ implies 48=h× 8

then,$\frac{48}{8}$=h×1

then h=6.

therefore the height of the trapezium is 6cm.

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