Question

3. In a Trapezium if the sum of the parallel sides is 16cm and the area is 48 cm. then its beige
(A) 5cm
(B) 6cm
(C) 7cm
(D) 8cm
4 The Perimeter of a parallelogram whose adjacent sides are x cm and y cm is
(A) 2(b + h) cm
(B) (x + y)cm
(C) 2(x+y)cm
(D) (x+y) cm​

Answer 1

3) Correct Question:-

• In a Trapezium if the sum of the parallel sides is 16cm and the area is 48 cm². then its height.

Answer:-

✬ The height of trapezium is 6 cm and the option B) is correct✬

Step-by-step explanation:

Given: Sum of parallel sides is 16 cm and the area of trapezium is 48 cm²

To find: Height of trapezium

Required formula:

• Area of trapezium = ½ × sum of parallel sides × height

Where,

• h = height

Then,

$\\ : \implies \sf{48 = \frac{1}{ \cancel{2}} \times \cancel{16} \times h } \\ \\ : \implies \sf{48 = 8 \times h} \\ \\ : \implies \sf{48 = 8h} \\ \\ : \implies \sf{h = \frac{ \cancel{48}}{ \cancel{8}}} \\ \\ : \implies \underline{ \boxed{\mathfrak{h = 6}}} \: \blue{ \bigstar}$

• ∴ Hence,The height of trapezium is 6 cm.

___________________________________

4) Question:

• The Perimeter of a parallelogram whose adjacent sides are x cm and y cm is

Answer:-

✬ Perimeter of parallelogram is 2(x + y)cm and option C) is correct ✬

Step-by-step explanation:

Given: Sides of parallelogram are x cm and y cm

To find: Perimeter of parallelogram

Required Formula:

• Perimeter of parallelogram = 2(a + b)

Where,

• P = Perimeter of parallelogram
• a = x
• b = y

Therefore, putting the values

$\\ : \implies \sf{P = 2(x + y)}$

• Hence,The Perimeter of parallelogram is 2(x + y)cm.

Answer 2

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In a trapezium the parallel sides are 4cm and 5cm and distance between them is 6cm find its area.

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➡Area of trapezium is 27cm²

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Parallel sides of trapezium are 4cm and 5cm

Height = 6cm

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Area of trapezium

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Area of trapezium

$\bf \purple{ \frac{1}{2} \times sum \: of \: ll \: sides \times h}$

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Area of trapezium =

$\bf \frac{1}{2} \times sum \: of \: ll \: sides \times h$

$\bf \implies \frac{1}{2} (4 + 5) \times 6⟹2$

$\bf \implies \frac{1}{\cancel2} \times 9 \times \cancel 6 \: 3$

$\bf \implies 9 \times 3⟹9×3$

$\bf \implies {27cm}^{2}⟹27cm$

• Therefore, Area of Trapezium is 27cm².

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