Question

3.
In a triangle PQR with right angle at Q, the value of ZP is .x, PQ=7 cm and OR -
24 cm, then find sin x and cos x.​

Answer 1

Answer:

Let me think that is Angle P = x

So..

From Pythagoras theorem

PR = √ (7)^2 + (24)^2

= 25..

Therefore sinx and cosx are.. In pic...

Hope this helps...

Plz mark brainliest...

Answer 2

Hello mate..

Here Is Your Answer:

GIVEN:

Right angled triangle is PQR with angle right angled at Q. The value of ∠P is x.

PQ = 7 cm and QR = 24 cm.

TO FIND:

• sin x
• cos x

SOLUTION:

By Pythagoras theorem,

PR² = PQ² + QR²

⠀⠀= 7² + 24²

PR² = 49 + 576

⠀⠀= 625

PR = √625 = 25

$\bold{Sin( X) = \frac{qr}{pr} } \\ = \bold{\frac{24}{25}}$

$\bold{ \cos(x) = \frac{pq}{pr}} \\ = \bold{\frac{7}{25} }$

HOPE THIS HELPS YOU..