3. In a vertical plane inside a smooth hollow thin tube a block of same mass as that of tube is released.When it is slightly disturbed,it moves towards right.By the time the block reaches the rightend of the tube then the displacement of the tube will be
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The displacement of the tube is equal to R/2
Let us make the following assumptions:
Let R be the radius of the tube,
m be the mass of the tube = the mass of the block
let the tube be displayed by x distance.
Then in the horizontal direction shift in the center of mass is zero. Hence we get,
mx = m(R-x)
=> x = R-x
=> 2x = R
=> x = R/2
Hence the displacement of the tube is equal to R/2
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Answer:
so R/2 is the ans .. hope it helped you
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