Question

3. In ΔABC, if AC = BC and CD bisects angle BCA, prove that ΔACD =congruent ΔBCD.​

Answer 1

Answer:

AC = BC (given)

CD = CD (given)

angle CDA = angle CDB (90°)

so, ∆ABC is congruent to ∆BCD ( by RHS rule)

hope it helps you..

Answer 2

Answer:

In ΔABC,

AC = BC (Given)

CD = CD (Common)

∠ACD = ∠DCB (CD is bisecting ∠BCA)

∴ ΔACD ≅ ΔBCD (By SAS congruency rule)

Hence, Proved.