Question

(3) In adjoining figure,
G is the point of
concurrence of
medians of ADEF.
Take point Honpl
ray DG such that
D-G-H and DG =
GH, then prove that
GEHF is a parallelogram.
​

Answer 1

Answer:

Step-by-step explanation:

Given G is the point of concurrence of medians of Δ DEF so the medians are divided in the ratio of 2:1 at the point of concurrence. Let O be the point of intersection of GH AND EF

⇒ DG = 2 GO

But DG = GH

⇒ 2 GO = GH

Also DO is the median for side EF.

⇒ EO = OF

Since the two diagonals bisects each other

⇒ GEHF is a ∥gram.

plz refer to the diagram given

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