Question

3) In an Ap 3,8,13, find 10th team.
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Answer 1

Correct Question:

In an A.P. 3, 8, 13 .... find the 10ᵗʰ term.

Answer :-

The 10ᵗʰ term of A.P. is 48.

Step-by-step explanation:

Given that,

• The sequence of an A.P. = 3, 8, 13 ...

∴ The first term and common difference are :-

Since,

8 - 3 = 5, 13 - 8 = 5, etc. the first term is 3 and the common difference is 5,

We know,

tₙ = a + (n - 1) d,

Where,

• tₙ = nth term
• a = first term
• n = number of terms
• d = common difference.

According the question,

⇒ tₙ = a + (n - 1) d

⇒ t₁₀ = 3 + (10 - 1) 5

⇒ t₁₀ = 3 + (9)5

⇒ t₁₀ = 3 + 45

⇒ t₁₀ = 48

Hence, The 10ᵗʰ term of A.P. is 48.

Answer 2

AP: 3,8,13,..

To find the 10th term:-

$⟹ \begin{gathered}a = 3 \\ d = 8 - 3 \\ d= 5 \\ n = 10 \\ \\ a(n) = a + (n - 1)d \\ a(10) = 3 + (10 - 1)(5) \\ a(10) = 3 + (9 \times 5) \\ a(10) = 3 + 45 \\ a(10) = 48\end{gathered}/$

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