Question

3. In an arithmetic sequence, the first term is 28 and the common difference is 50. In a geometric sequence, the first
term is 1 and the common ratio is 1.5. Find the least value of n such that the nth term of the geometric sequence is
greater than the nth term of the arithmetic sequence.

can someone pls answer this question?

Answer 1

Answer:

Sn = a + (a + d)+(a + 2d) + ... + (ℓ − 2d)+(ℓ − d) + ℓ. 2 n(a + ℓ) . We have found the sum of an arithmetic progression in terms of its first and last terms, a and ℓ, and the number of terms n.