Question

3. In an experiment, an iron sphere of mass
390 g displaces 5 cm of water. What is the
density of iron? ​

Answer 1

Answer:

hope it helps ☺️

^_^

Explanation:

Let the density and radius of iron be d and r respectively.

So,

3

4

πr

3

×d=20×10

−3

-----------(1)

and 0.5m/s=

9η

2gr

2

(T−σ)

---------------(2)

Now, in 2

nd

case,

3

4

πr

1

3

×d=540×10

−3

⇒

r

3

r

1

3

=27⇒r

1

=3r[Dividing from(1)]

So, Terminal Velocity =

9η

2g(3r)

2

(T−σ)

Terminal Velocity =

9η

2gr

2

(T−σ)

×9 [from(2)]

⇒T.V=9×0.5m/s

=4.5m/s

Answer 2

Answer:

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