Question

3. In an isosceles triangle, an altitude is drawn from the vertical angle to the base. Prove
that the foot of altitude is the mid-point of the base.​

Answer 1

Answer:

Step-by-step explanation:

being an isosceles triangle

in ΔACD and ΔCDB

CD=CD (common )

CA=CB ( equal opposite sides)

∠ A=∠ B ( angle opposite to opposite sides are also equal )

therefore : ΔACD and ΔCDB are congruent by ASA rule

so , AD=DB by CPCT

So, its true