.3) In APQR, mZQ=90°, If /(QR) =6cm and /(PQ)=8cm. What
is the length of seg (PR)?
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Answer:
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Step-by-step explanation:
It is given that
PQ=8cm and QR=6cm
∠PQR=90
∘
Using Pythagoras Theorem
PR
2
=PQ
2
+QR
2
Substituting the values
PR
2
=8
2
+6
2
By further calculation
PR
2
=64+36=100
PR=√100
So we get
PR=10cm
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