Question

3) In each case find the smallest number
which when divided by each of the
numbers gives the common remainder.
(0) 16, 24, 48 : remainder 5
(ii) 22, 33, 121 : remainder 1
(iii) 80, 108, 64 : remainder 5
(iv) 63, 12, 84 : remainder 8
(V/120, 144,96
: remainder 3​

Answer 1

Step-by-step explanation:

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