Question

3) In each case find the smallest number
which when divided by each of the
numbers gives the common remainder. 120,144,96 common remainder 3
​

Answer 1

Answer:  9, 3, 3

Step-by-step explanation:

for 120;

if remainder is 3, then the number must be divisible by 120-3 => 117//

Therefore, smallest number will be 9, as 9*13 = 117

Similarily,

For 144; 3

For 96; 3

Answer 2

Step-by-step explanation:

9,3,3

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