Math, asked by ohwellins, 1 month ago

3. In Fig. 6.15, Z PQR = Z PRQ, then prove that PQS = Z PRT.

send me the answer ASAP​

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Answers

Answered by upendra44506
0

Step-by-step explanation:

Given that, ∠PQR=∠PRQ

from above figure, we have,

∠PQS=180−∠PQR

∠PRT=180−∠PRQ

∠PRT=180−∠PQR

∴∠PQS=∠PRT

Answered by BlessOFLove
2

{\tt{Question}}\: \purple☟

In Fig. 6.15, Z PQR = Z PRQ, then prove that PQS = Z PRT.

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\red&#9998{\tt{Answer}}\: \orange☟

⠀⠀	&#9679\purple{\bf{See \:the \:attachment}}\red{⇑}

	&#9679\orange{\bf{Question\: solved}}\: \green✔

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All necessary formulas⤵️

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\purple{\boxed{\bf{Angle\:sum\: property}}}

Angle sum property of triangle states that the sum of interior angles of a triangle is 180°. Proof .Thus, the sum of the interior angles of a triangle is 180°.

\blue{\tt{Example:-}}

\red{\boxed{a+b+c=180°}}

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\orange{\boxed{\bf{Alternate\: interior\:angle}}}

Alternate interior angles are angles formed when two parallel or non-parallel lines are intersected by a transversal.Alternate interior angles are equal if the lines intersected by the transversal are parallel.

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\orange\star{\bf{\red{\underbrace{complementary \:angle}}}}\red\star

The sum of 2 numbers=90°

example  a−b=90°

how to find "a" if a is not mentioned

\red{\underbrace{\bf{\orange{Given࿐}}}}

a= \: ?

b = 40

a+40=\:90°

a=90-40°

a=50°

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\pink\star{\bf{\purple{\underbrace{supplementary\: angle}}}}\red\star

The sum of two numbers= \:180°

example a+b=180°

how to find "a" if a is not mentioned

Given

a= \:?

b =\: 40

a+40=180°

a=180-40°

a=140°

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\orange\star{\bf{\green{\underbrace{Adjacent \:angle}}}}\red\star

If there is a common ray between {\bf&#x2220}a and {\bf&#x2220}b so it is a adjacent angle.

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\orange\star{\bf{\blue{\underbrace{Vertical\: opposite\: angle }}}}\red\star

Vertical angles are pair angles formed when two lines intersect. Vertical angles are sometimes referred to as vertically opposite angles because the angles are opposite to each other.

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\orange\star{\bf{\orange{\underbrace{lenear\: pair \:of\: angles}}}}\red\star

Here {\bf&#x2220}a+{\bf&#x2220}b=180°.

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