3. In Fig. 6.30, if AB || CD, EFI CD and
Z GED=126°, find Z AGE, Z GFF and ZFGE.
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Angle AGE = and let GED =126 (ALTERNATE INTERIOR ANGLE PROPERTY)
angle GFE =90 (AB||CD => IF EF IS PERPENDICULAR TO ONE LINE, THEN IT IS PERPENDICULAR TO THE OTHER ALSO)
since, angle AGE = 126
angle FGE = 180-126 (LINEAR PAIR)
= 54
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