Question

3. In Fig. 6.53, ABD is a triangle right angled at A
and AC is perpendicular to BD. Show that
(i) AB^2 = BC.BD
(ii) AC^2= BC.DC
(ii) AD^2= BD.CD.... ncert ex 6.5 class 10 please give the answer​

Answer 1

Step-by-step explanation:

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