Question

3. In Fig 7.33, BD and CE are altitudes of AABC such that BD=CE
(1) State the three pairs of equal parts in ACBD and ABCE.
(ii) Is ACBD: ABCE? Why or why not?
(ii) Is ZDCB = ZEBC? Why or why not?
ale with AB=AC and AD:​

Answer 1

Given,  in \bigtriangleup CBD and \bigtriangleup BCE.

BD= CE

\angle CEB=\angle BDC=90^o  

\overline{ BC} = \overline{ CB}

 

ii) So, By RHS Rule of congruency, we conclude:

\bigtriangleup CBD\cong \bigtriangleup BCE

 

iii) Since both the triangle are congruent, all parts of one triangle are equal to their corresponding part from another triangle.

So.

\bigtriangleup CBD\cong \bigtriangleup BCE.