Question

3. In Fig. 7.49,2 B<< A and ZC< ZD. Show that
AD<BC.​

Answer 1

✨✨Answer is here✨✨

➡️✨✨see this pic✨✨

✔️✔️

Answer 2

in COD

$\implies$COB + 1 + 2 ≈ 180°

$\implies$COB ≈ 180° - ( 1 + 2)

$\implies$COB ≈ 180° - $( \frac{1}{2} c + \frac{1}{2} d)$

$\implies$COB ≈ 180° - $\frac{1}{2}$( C + D)

$\implies$COB ≈ 180° -$\frac{3}{2}$[ 360° - (A + B) ]

$\implies$COB ≈ 180° - 180° + $\frac{1}{2}$(A + B)

$\implies$COB ≈$\frac{1}{2}$(A + B)