Question

3. In fig., E is the mid-point of side AD of a trapezium ABCD,
with AB || DC. A line through E parallel to AB meets BC in
F. Show that F is the mid-point of BC.​

Answer 1

Answer:

Given:

ABCD is a trapezium where AB||DC

E is the mid point of AD ,i.e.,AE = DE & EF || AB

Proof:

Let EF intersect DB at G.

In triangle ABD

E is the mid point of AD and EG || AB

Therefore,

G will be the mid point of DB