3.In figure 6,AB=AD and <BAC=<DAC.Prove that line segment CA bisects <BCD.
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Answer:
(i)
∠DAC=∠BAC
∠DCA=∠BCA
AC=AC
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Step-by-step explanation:
AB = AD (given)
angle BAC = angle DAC ( given)
AC = AC ( common)
hence ,∆ BAC is congruent to ∆ DAC
angle BCA = angle DCA ( cpct)
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