Question

3. In parallelogram ABCD, A= B
parallelogram ABCD, A B +50°, then find the measure
of each angle of the quadrilateral ABCD.​

Answer 1

Answer:

$\angle \: A = \angle \: C = 115° \\ \angle \: B = \angle \: D= 65°$

Step-by-step explanation:

We know that in a parallelogram Sum of adjacent angles are 180°.

$\angle \: A + \angle \: B = 180°\\ \\ ...eq1$

given that

$\angle \: A = \angle \: B + 50° \\ \\\angle \: A - \angle \: B = 50°...eq2$

from equation 1 and 2

$2\angle \: A = 230° \\ \\ \angle \: A = 115°$

$\angle \:C = 115°$

because opposite angles are equal.

$\angle \: B = \angle \: D = 65 °$

Hope it helps you.

Answer 2

Answer:

angle A=115°

angle B=115°

angle C=65°

angle D=65°