Math, asked by rahulsingh21334, 10 months ago

3. In parallelogram ABCD, A= B
parallelogram ABCD, A B +50°, then find the measure
of each angle of the quadrilateral ABCD.​

Answers

Answered by hukam0685
5

Answer:

\angle \: A = \angle \: C = 115° \\ \angle \: B = \angle \: D= 65° \\

Step-by-step explanation:

We know that in a parallelogram Sum of adjacent angles are 180°.

 \angle \: A + \angle \: B = 180°\\  \\ ...eq1

given that

\angle \: A = \angle \: B + 50° \\  \\\angle \: A - \angle \: B = 50°...eq2 \\

from equation 1 and 2

2\angle \: A = 230° \\  \\ \angle \: A = 115° \\

\angle \:C = 115° \\  \\

because opposite angles are equal.

\angle \: B  = \angle \: D = 65 °\\  \\

Hope it helps you.

Answered by charisma47
7

Answer:

angle A=115°

angle B=115°

angle C=65°

angle D=65°

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