Question

3) In ∆PQR angle P = 70° angle R = 45 then angle Q=?
6) 65° c 55° 2) 75°
a) 63​

Answer 1

$\huge \mathtt {♡Answer:}$

$\large P + R + Q = 180° \\(Angle\: sum\:property)$

$\large70° + 45° + Q = 180°</p><p>\\\:\:\:\:\:\:\:\:\:115° + Q = 180°</p><p>\\\:\:\:\:\:\:\:\:\:\:\:\:Q = 180° - 115°</p><p> \\\:\:\:= 65°$

Answer 2

Step-by-step explanation:

In ∆ PQR, P=70° and R=45° to find : Q=? now, In ∆PQR, by using sum of angle of a ∆s <p+<Q+<R=180° then, 70°+<Q+45°=180° 115°+<Q=180° <Q=180°-115° <Q=65°